Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.3 - Solving Systems of Linear Equations by Addition - Exercise Set - Page 308: 37

Answer

$(-\frac{2}{3}, \frac{2}{5})$

Work Step by Step

$\frac{3}{5}x-y=-\frac{4}{5}$ $3x+\frac{y}{2}=-\frac{9}{5}$ Multiply first equation by 5 and second equation by 10. $3x-5y=-4$ $30x+5y=-18$ Add both equations. $33x=-22$ $x=-\frac{2}{3}$ Solve for $y$. $\frac{3}{5}x-y=-\frac{4}{5}$ $\frac{3}{5}(-\frac{2}{3})-y=-\frac{4}{5}$ $-\frac{2}{5}-y=-\frac{4}{5}$ $y=\frac{2}{5}$ $x=-\frac{2}{3}$ $y=\frac{2}{5}$ $(-\frac{2}{3}, \frac{2}{5})$
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