Answer
$x=3\\y=12$
Work Step by Step
$\begin{cases}
\frac{x}{2}+\frac{y}{8}=3\\
x-\frac{y}{4}=0
\end{cases}$
Multiply the first equation by 8 and the second equation by 4 to get rid of the fractions:
$\begin{cases}
4x+y=24\\
4x-y=0.
\end{cases}$
Add the two equations to remove the y:
$8x=24$.
Solve for x:
$x=\frac{24}{8}=3$.
Substitute $x=3$ in the second equation:
$3-\frac{y}{4}=0$.
Solve for y:
$\frac{y}{4}=3$
$y=3*4=12$.
Our two solutions are
$x=3\\y=12$.
