Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set: 35

Answer

x = $\frac{1}{2}$ y = 2

Work Step by Step

x = $\frac{3}{4}$y -1 8x - 5y = -6 substitude x to the second equation 8($\frac{3}{4}$y -1 ) - 5y = -6 use the distributive property 6y - 8 - 5y = -6 simplify y = 8 - 6 add 8 to both sides y = 2 substitude y = 2 to the first equation x = $\frac{3}{4}$ (2) -1 x = $\frac{3}{2}$ -$\frac{2}{2}$ x = $\frac{1}{2}$
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