Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set: 28

Answer

x = -3 y = 5

Work Step by Step

-x + 3y = 18 - 3x + 2y = 19 to the first equation minus 3y to both sides -x + 3y - 3y = 18 - 3y -x = 18 - 3y multiply by -1 both sides -1 ( -x ) = -1 ( 18 - 3y ) use the distributive property x = -18 + 3y substitude x to the second equation -3 ( -18 + 3y ) + 2y = 19 use the distributive property 54 - 9y + 2y = 19 54 - 7y = 19 minus 54 to both sides 54 -7y - 54 = 19 - 54 -7y = - 35 divide by -7 $\frac{-7y}{-7}$ = $\frac{ -35}{-7}$ y = 5 substitude y = 5 to x = -18 + 3y x = -18 + $3\times5$ x = -18 + 15 x = -3
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