## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set: 27

x = -6 y = 2

#### Work Step by Step

-x + 2y = 10 -2x + 3y = 18 minus 2y to both sides to the first equation -x + 2y - 2y = 10 - 2y -x = 10 - 2y multiply by -1 both sides -1 ( -x ) = -1 ( 10 - 2y ) use the distributive property x = -10 + 2y distributive x to the second equation -2 ( -10 + 2y ) + 3y = 18 use the distributive property 20 - 4y + 3y = 18 20 -y = 18 minus 20 to both sides 20 - y - 20 = 18 - 20 -y = -2 multiply by -1 y = 2 substitude y to x = -10 + 2y x = -10 + $2\times2$ x = -10 + 4 x = -6

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