Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set: 26

Answer

x = -5 y = - 3

Work Step by Step

2x - y = -7 4x - 3y = -11 to the first equation ,minus 2x to both sides 2x - y - 2x = -7 - 2x -y = -7 - 2x multiply both sides by -1 y = -1 (-7 - 2x ) use the distributive property y = 7 + 2x substitude y to the second equation 4x - 3 ( 7 + 2x ) = -11 4x - 21 - 6x = -11 -2x -21 = -11 add 21 to both sides -2x -21 + 21 = -11 + 21 -2x = 10 divide both sides by -2 $\frac{-2x}{-2}$ = $$\frac{10}{-2} x = -5 substitude x to y = 7 + 2x y = 7 + 2 ( - 5) y = 7 - 10 y = -3
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