Answer
Please see the graph.
Axis of symmetry: $x=1$
Vertex: $(1, 1)$
Work Step by Step
$f(x)=-3(x-1)^2+1$
$(fx)=-3*(x-1)(x-1)+1$
$f(x)=-3*(x*x+x*(-1)+(-1)*x+(-1)(-1))+1$
$f(x)=-3*(x^2-x-x+1)+1$
$f(x)=-3(x^2-2x+1)+1$
$f(x)=-3x^2+6x-3+1$
$f(x)=-3x^2+6x-2$
$a=-3$, $b=6$, $c=-2$
$x=-b/2a$ is the vertex.
$x=-b/2a$
$x=-6/2*-3$
$x=-6/-6$
$x=1$
$f(x)=-3(x-1)^2+1$
$f(1)=-3(1-1)^2+1$
$f(1)=-3*0^2+1$
$f(1)=-3*0+1$
$f(1)=0+1$
$f(1)=1$
