Answer
Please see the graph.
Axis of symmetry: $x=-5$
Vertex: $(-5, 0)$
Work Step by Step
$G(x)=(x+5)^2$
$G(x)=(x+5)(x+5)$
$G(x)=x*x+x*5+5*x+5*5$
$G(x)=x^2+5x+5x+25$
$G(x)=x^2+10x+25$
$a=1$, $b=10$, $c=25$
$x=-b/2a$ is the vertex.
$x=-b/2a$
$x=-10/2*1$
$x=-10/2$
$x=-5$
$G(x)=(x+5)^2$
$G(-5)=(-5+5)^2$
$G(-5)=0^2$
$G(-5)=0$
