Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Review - Page 829: 36

Answer

$(-∞, -6) U (-3/4, 0) U (5, ∞)$

Work Step by Step

$(4x+3)(x-5)/(x)(x+6) > 0$ $4x+3=0$ $4x+3-3=0-3$ $4x=-3$ $4x/4=-3/4$ $x=-3/4$ $x-5=0$ $x-5+5=0+5$ $x=5$ $x=0$ $x+6=0$ $x+6-6=0-6$ $x=-6$ Five regions to test: $(-∞, -6)$, $(-6, -3/4)$, $(-3/4, 0)$, $(0, 5)$, $(5, ∞)$ Let $x=-10$, $x=-2$, $x=-1/2$, $x=2$, $x=10$ $x=-10$ $(4x+3)(x-5)/(x)(x+6) > 0$ $(4*-10+3)(-10-5)/(-10)(-10+6) > 0$ $(-40+3)(-15)/(-10)(-4) > 0$ $(-37*-15)/40 > 0$ $555/40 > 0$ $13.875 > 0$ (true) $x=-2$ $(4x+3)(x-5)/(x)(x+6) > 0$ $(4*-2+3)(-2-5)/(-2)(-2+6) > 0$ $(-12+3)(-7)/(-2)(4) > 0$ $(-9)(-7)/(-8) > 0$ $63/-8 > 0$ (false) $x=-1/2$ $(4x+3)(x-5)/(x)(x+6) > 0$ $(4*-1/2+3)(-1/2-5)/(-1/2)(-1/2+6) > 0$ $(-2+3)(-11/2)/(-1/2)((11/2) >0$ $(1)(-11/2)/(-11/4) >0$ $-11/2 / -11/4 > 0$ $-5.5 / -2.75 >0$ $2 > 0$ (true) $x=2$ $(4x+3)(x-5)/(x)(x+6) > 0$ $(4*2+3)(2-5)/(2)(2+6) > 0$ $(8+3)(-3)/(2)(8) > 0$ $11*-3/16 > 0$ $-33/16 > 0$ (false) $x=10$ $(4x+3)(x-5)/(x)(x+6) > 0$ $(4*10+3)(10-5)/(10)(10+6) > 0$ $(40+3)(5)/(10)(16) >0$ $(43)/(2*16) >0$ $43/32 > 0$ (true)
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