Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Review: 14

Answer

$x_{1}= 0$ and $x_{2}= -5$

Work Step by Step

Given $x^2+5x=0$ $a=1, \ b=5, \ c=0$ Using the quadratic formula: $\dfrac{-\ b \pm \sqrt{b^2-4ac}}{2a} ,$ we have: $\dfrac{- 5 \pm \sqrt{5^2-4\times 1\times 0}}{2\times 1} = \dfrac{- 5 \pm \sqrt{25-0}}{2} = \dfrac{- 5 \pm \sqrt{25}}{2} = \dfrac{- 5 \pm 5}{2} $ Therefore, the solutions are $x_{1}= \dfrac{- 5 + 5}{2} = \dfrac{0}{2} = 0$ and $x_{2}= \dfrac{- 5 - 5}{2} = \dfrac{-10}{2} = -5$
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