Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Test: 18

Answer

$\sqrt {6}+\sqrt 2-4\sqrt 3-4$

Work Step by Step

$(\sqrt 2-4)(\sqrt 3+1)$ =$\sqrt 2(\sqrt 3+1)-4(\sqrt 3+1)$ =$\sqrt 2\sqrt 3+\sqrt 2-4\sqrt 3-4$ =$\sqrt {2\times3}+\sqrt 2-4\sqrt 3-4$ =$\sqrt {6}+\sqrt 2-4\sqrt 3-4$
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