Answer
$-a^{6}b^{3}$
Work Step by Step
$\sqrt[3] {-a^{18}b^{9}}$
=$(-a^{18}b^{9})^{\frac{1}{3}}$
=$(-1)^{\frac{1}{3}}\times (a^{18})^{\frac{1}{3}}\times (b^{9})^{\frac{1}{3}}$
=$(-1)\times (a^{6})\times (b^{3})$
=$-a^{6}b^{3}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Test - Page 750: 6
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