Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Test: 5

Answer

$\frac{4x^{2}}{9}$

Work Step by Step

$(\frac{8x^{3}}{27})^{\frac{2}{3}}$=$(\frac{2^{3}\times x^{3}}{3^{3}})^{\frac{2}{3}}$=$(\frac{2^{2}\times x^{2}}{3^{2}})$=$\frac{4x^{2}}{9}$
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