Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 104

Answer

$\frac{\sqrt {3x}}{6}$

Work Step by Step

$\sqrt \frac{x}{12}$ =$\frac{\sqrt x}{\sqrt {12}}$ =$\frac{\sqrt x}{\sqrt {4\times3}}$ =$\frac{\sqrt x}{2\sqrt {3}}$ =$\frac{\sqrt x}{2\sqrt {3}}\times\frac{2\sqrt {3}}{2\sqrt {3}}$ =$\frac{\sqrt x \times2\sqrt {3} }{2\sqrt {3}\times2\sqrt {3}}$ =$\frac{2\sqrt {3x}}{4(3)}$ =$\frac{\sqrt {3x}}{2(3)}$ =$\frac{\sqrt {3x}}{6}$
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