Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 112

Answer

$\frac{6}{\sqrt {2y}}$

Work Step by Step

$\sqrt \frac{18}{y}$ =$\frac{\sqrt {18}}{\sqrt y}$ =$\frac{\sqrt {2\times9}}{\sqrt y}$ =$\frac{3\sqrt {2}}{\sqrt y}$ =$\frac{3\sqrt {2}}{\sqrt y}\times\frac{3\sqrt {2}}{3\sqrt {2}}$ =$\frac{3\sqrt {2}\times3\sqrt {2}}{\sqrt y\times3\sqrt {2}}$ =$\frac{9\times\sqrt {2}\times\sqrt {2}}{3\sqrt {2y}}$ =$\frac{9\times2}{3\sqrt {2y}}$ =$\frac{6}{\sqrt {2y}}$
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