Answer
$\frac{3\sqrt y+6}{y-4}$
Work Step by Step
$\frac{3}{\sqrt y-2}\times\frac{\sqrt y+2}{\sqrt y+2}$
=$\frac{3(\sqrt y+2)}{(\sqrt y-2)(\sqrt y+2)}$
=$\frac{3\sqrt y+6}{(\sqrt y)^{2}-2^{2}}$
=$\frac{3\sqrt y+6}{y-4}$
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