Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review - Page 748: 109

Answer

$\frac{3\sqrt y+6}{y-4}$

Work Step by Step

$\frac{3}{\sqrt y-2}\times\frac{\sqrt y+2}{\sqrt y+2}$ =$\frac{3(\sqrt y+2)}{(\sqrt y-2)(\sqrt y+2)}$ =$\frac{3\sqrt y+6}{(\sqrt y)^{2}-2^{2}}$ =$\frac{3\sqrt y+6}{y-4}$
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