Answer
{$35$}
Work Step by Step
Step 1: $\sqrt[3] {2x-6}=4$
Step 2: $(\sqrt[3] {2x-6})^{3}=4^{3}$
Step 3: $2x-6=64$
Step 4: $2x=64+6$
Step 5: $2x=70$
Step 6: $x=\frac{70}{2}=35$
Therefore, the solution set is {$35$}.
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