Answer
$\dfrac{3+3(5+3)}{3^{2}+1}=\dfrac{27}{10}$
Work Step by Step
$\dfrac{3+3(5+3)}{3^{2}+1}$
First, perform the operation inside the parentheses in the numerator:
$\dfrac{3+3(5+3)}{3^{2}+1}=\dfrac{3+3(8)}{3^{2}+1}=...$
Now, evaluate the product in the numerator and after that, the sum:
$...=\dfrac{3+24}{3^{2}+1}=\dfrac{27}{3^{2}+1}=...$
Finally, in the denominator, evaluate the exponential expression and then the sum:
$...=\dfrac{27}{9+1}=\dfrac{27}{10}$