Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 1 - Section 1.3 - Exponents, Order of Operations, and Variable Expressions - Exercise Set - Page 28: 41

Answer

$\dfrac{3+3(5+3)}{3^{2}+1}=\dfrac{27}{10}$

Work Step by Step

$\dfrac{3+3(5+3)}{3^{2}+1}$ First, perform the operation inside the parentheses in the numerator: $\dfrac{3+3(5+3)}{3^{2}+1}=\dfrac{3+3(8)}{3^{2}+1}=...$ Now, evaluate the product in the numerator and after that, the sum: $...=\dfrac{3+24}{3^{2}+1}=\dfrac{27}{3^{2}+1}=...$ Finally, in the denominator, evaluate the exponential expression and then the sum: $...=\dfrac{27}{9+1}=\dfrac{27}{10}$
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