## Algebra: A Combined Approach (4th Edition)

$\dfrac{3}{4}\cdot\dfrac{1}{2}+\dfrac{2}{3}=\dfrac{25}{24}$
$\dfrac{3}{4}\cdot\dfrac{1}{2}+\dfrac{2}{3}$ Evaluate the product and after that, the sum: $\dfrac{3}{4}\cdot\dfrac{1}{2}+\dfrac{2}{3}=\dfrac{3}{8}+\dfrac{2}{3}=\dfrac{(3)(3)+(2)(8)}{(8)(3)}=\dfrac{9+16}{24}=\dfrac{25}{24}$