Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 1 - Section 1.3 - Exponents, Order of Operations, and Variable Expressions - Exercise Set: 37

Answer

$\dfrac{19-3\cdot5}{6-4}=2$

Work Step by Step

$\dfrac{19-3\cdot5}{6-4}$ First, evaluate the product in the numerator and after that, the substraction that will remain in the numerator: $\dfrac{19-3\cdot5}{6-4}=\dfrac{19-15}{6-4}=\dfrac{4}{6-4}=...$ Finally, evaluate the substraction in the denominator and then, the division: $...=\dfrac{4}{2}=2$
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