Answer
$\dfrac{19-3\cdot5}{6-4}=2$
Work Step by Step
$\dfrac{19-3\cdot5}{6-4}$
First, evaluate the product in the numerator and after that, the substraction that will remain in the numerator:
$\dfrac{19-3\cdot5}{6-4}=\dfrac{19-15}{6-4}=\dfrac{4}{6-4}=...$
Finally, evaluate the substraction in the denominator and then, the division:
$...=\dfrac{4}{2}=2$
