Answer
$\dfrac{15-|3-1|}{12-3\cdot2}=\dfrac{13}{6}$
Work Step by Step
$\dfrac{15-|3-1|}{12-3\cdot2}$
In the numerator, evaluate first the operation inside absolute value bars and then evaluate the substraction. In the denominator, evaluate the product first and after that, the substraction:
$\dfrac{15-|3-1|}{12-3\cdot2}=\dfrac{15-|2|}{12-6}=\dfrac{13}{6}$