Answer
$5x^2y \sqrt {2xyz}$
The constant value under the radical sign is $2$.
Work Step by Step
Rewrite the radicand as the product of perfect squares and other factors:
$\sqrt {25 \cdot 2 \cdot x^4 \cdot x \cdot y^2 \cdot y \cdot z}$
Take the square roots of all perfect squares:
$5 \cdot x^2 \cdot y \sqrt {2 \cdot x \cdot y \cdot z}$
Multiply to simplify:
$5x^2y \sqrt {2xyz}$
The constant value under the radical sign is $2$.
