Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - Cumulative Standards Review - Multiple Choice - Page 560: 15

Answer

$x = 1$

Work Step by Step

Label the equations first: $\begin{align*} 2x + y = 6 \quad (1)\\ y - 3 = x \quad (2)\end{align*}$ Use equation $(2)$ to substitute for $x$ in equation $1$: $2(y - 3) + y = 6$ Distribute and multiply: $2y - 6 + y = 6$ Combine like terms: $3y - 6 = 6$ Add $6$ to each side of the equation: $3y = 12$ Divide each side of the equation by $3$: $y = 4$ Substitute this value for $y$ into equation $(2)$ to solve for $x$: $4 - 3 = x$ Subtract to simplify: $x = 1$
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