Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - Cumulative Standards Review - Multiple Choice - Page 560: 13

Answer

$x = 5$

Work Step by Step

Factor all expressions to their simplest forms: $\dfrac{5}{2(x - 1)} = \dfrac{15}{(x - 1)(x + 1)}$ The least common denominator, or LCD, incorporates all factors in the denominators of the fractions. In this case, the LCD is $2(x - 1)(x + 1)$. Convert each fraction to an equivalent one by multiplying its numerator with whatever factor is missing between its denominator and the LCD: $\dfrac{5(x + 1)}{2(x - 1)(x + 1)} = \dfrac{15(2)}{2(x - 1)(x + 1)}$ Multiply to simplify: $\dfrac{5x + 5}{2(x - 1)(x + 1)} = \dfrac{30}{2(x - 1)(x + 1)}$ Multiply each side by the LCD to eliminate the fractions: $5x + 5 = 30$ Subtract $5$ from each side of the equation: $5x = 25$ Divide each side of the equation by $5$: $x = 5$
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