Answer
0.570 mm.
Work Step by Step
Apply the formula $y=m(\frac{\lambda}{2})$ for m=1800.
$$y=m(\frac{\lambda}{2})$$
$$y=1800(\frac{633\times10^{-9}m}{2})=5.70\times10^{-4}m$$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 35 - Interference - Problems - Exercises - Page 1182: 35.33
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