University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 14 - Periodic Motion - Problems - Exercises - Page 463: 14.59

Answer

(a) The amount of energy that was lost is 0.30 J (b) The energy could have been transformed into heat inside the spring.

Work Step by Step

(a) We can find the initial amount of energy in the system. $E_1 = \frac{1}{2}kA^2$ $E_1 = \frac{1}{2}(250~N/m)(0.060~m)^2$ $E_1 = 0.45~J$ We can find the amount of energy in the system after eight cycles. $E_2 = \frac{1}{2}kA^2$ $E_2 = \frac{1}{2}(250~N/m)(0.035~m)^2$ $E_2 = 0.15~J$ We can find the amount of energy that was lost. $E_1-E_2 = 0.45~J-0.15~J = 0.30~J$ (b) The energy could have been transformed into heat inside the spring.
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