Answer
$n=1.3\times 10^5m^{-1}$
Work Step by Step
We know that
$n=\frac{B}{\mu_{\circ}I}$
We plug in the known values to obtain:
$n=\frac{17}{4\pi \times 10^{-7}(105)}$
$n=1.3\times 10^5m^{-1}$
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