Answer
$3.1\times 10^{-8}A$
Work Step by Step
We can find the required current as follows:
$I=\frac{Q}{t}$
We plug in the known values to obtain:
$I=\frac{85\times 10^{-6}C}{0.75\times 3600s}$
$I=3.1\times 10^{-8}A$
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