Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems: 27


$\Sigma \tau = mg \mathcal{l}_2-mg \mathcal{l}_1$ $clockwise$.

Work Step by Step

There is a torque due to the weight on the left that tends to accelerate the rod counterclockwise and a clockwise torque due to the weight on the right. Let’s call clockwise the positive direction. $$\Sigma \tau = mg \mathcal{l}_2-mg \mathcal{l}_1$$ The net torque is clockwise.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.