Answer
See the sketch below.
Work Step by Step
To sketch this graph, we can use the same data from the previous problem at which
$$I=\dfrac{V_B-V_D}{R}$$
where $V_B=2\;\rm V$, and $V_D=0.65\;\rm V$ as we figured it out there.
Now solving for $R$;
$$R=\dfrac{2-0.65}{I}$$
Now we can sketch this resistance as a function of current, as we see in the figure below.
Noting that the data, in the graph below, are not accurate.
