Answer
$\phi=14.0^{\circ}$
Work Step by Step
Apply equation 25–10 with m = 1.
$$m\lambda=2dsin\phi$$
$$\phi=sin^{-1}\frac{m \lambda}{2d}= sin^{-1}\frac{(1)(0.138nm)}{2(0.285nm)}$$
$$\phi=14.0^{\circ}$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 25 - Optical Instruments - Problems - Page 742: 60
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