Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 22 - Electromagnetic Waves - Problems - Page 642: 35

Answer

0.16 meters

Work Step by Step

Use equation 22–4, $c=\lambda f$. $$\lambda=\frac{c}{f}=\frac{3.00\times10^8m/s }{1.9\times10^{9}Hz}$$ $$\lambda=0.16m$$
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