Answer
1.19 A
Work Step by Step
Use equation 20–8 for the magnetic field inside a solenoid.
$$B=\frac{\mu_oNI}{\mathcal{l}}$$
$$I=\frac{B\mathcal{l}}{\mu_oN}$$
$$=\frac{(4.65\times10^{-3}T)(0.300m)}{(4\pi \times10^{-7} T\cdot m/A)(935)} $$
$$=1.19A$$
