Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 4 - Forces and Newton's Laws of Motion - Problems - Page 114: 26

Answer

The frictional force acting on the vehicle has a magnitude of $130N$.

Work Step by Step

Mass of the vehicle $m=5.9\times10^3kg$ In tests on earth, to achieve $a=0.22m/s^2$, the drive force required is, according to Newton's 2nd Law, $$F=ma=1.3\times10^3N$$ We know from Newton's 2nd Law and Conceptual Example 7 that the calculated $F$ above is the same on earth and on the moon, as mass $m$ does not change as the vehicle goes to the moon. Therefore, the increase in the required drive force on the moon is attributed to friction. We have $F_{moon}=1.43\times10^3N$ $$F_{moon}=F+f$$ $$f=F_{moon}-F=130N$$
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