Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Check Your Understanding - Page 12: 10


A and B are perpendicular to each other

Work Step by Step

$|A+B|$=$|C|$ $\implies$$\sqrt {a^{2}+b^{2}+2abcos(\theta)}$ = $|C|$ = $\sqrt {a^{2}+b^{2}}$ $\therefore$ $cos(\theta) = 0$ or $\theta = 90^{\circ}$ so, $A$ and $B$ are perpendicular to each other
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