Answer
$(80\,km/h)\hat{i}-(60\,km/h)\hat{j}$
Work Step by Step
The unit vector along the negative direction of y-axis is $-\hat{j}$
Then, $\vec{v_M}= -(60\,km/h)\hat{j}$
The unit vector along the negative direction of x-axis is $-\hat{i}$
Therefore, $v_{P}= -(80\,km/h)\hat{i}$
We want to find $v_{MP}$.
$v_{MP}= v_{M}-v_{P}=-(60\,km/h)\hat{j}- (-(80\,km/h)\hat{i}) $
$=(80\,km/h)\hat{i}-(60\,km/h)\hat{j}$
