Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 34 - Images - Problems - Page 1046: 139d

Answer

The image is not inverted.

Work Step by Step

With $m_2=-i_2 / p_2=1 / 6$, the net magnification is $m=m_1 m_2=2 / 3>0$. The fact that $m$ is positive means that the orientation of the final image is the same as the (original) object. Therefore, the image is not inverted.
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