Answer
$q_2=20.0\mu C$
Work Step by Step
We can find the charge on $C_2$ as
$q_2=C_2V_2$
We plug in the known values to obtain:
$q_2=2.0\times 10^{-6}\times 10.0=20.0\mu C$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 740: 15f
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