Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 548: 102

Answer

$ 6.632\times 10^{-4}\ m$

Work Step by Step

It is given: initial temperature $T_1 = -16^{\circ} C$ final temperature $T_2 =32^{\circ} C$ initial diameter $L= 170\ in =170 \ in(\frac{2.54\ cm}{1\ in}) = 431.8\ cm$ Linear expansion coefficient$(\alpha)$ for pyrex glass is $3.2\times 10^{-6}/^{\circ} C$. The change in diameter is given by; $\Delta L =L\alpha(T_2-T_1)$ $\Delta L =(431.8\ cm)(3.2\times 10^{-6}/^{\circ} C)((32^{\circ} C-(-16^{\circ} C))$ $\Delta L = 0.06632\ cm$ $\Delta L = 6.632\times 10^{-4}\ m$
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