Answer
$$3.3 \times 10^{2} \mathrm{W}$$
Work Step by Step
Finally, with $T_{\mathrm{env}}=193 \mathrm{K} $
(and still with $A=0.9 \mathrm{m}^{2}) $ we obtain $$\left|P_{\mathrm{net}}\right|=3.3 \times 10^{2} \mathrm{W}$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 547: 87c
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