Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 545: 70

Answer

$V=35.7m^3$

Work Step by Step

We know that, $V=\frac{m}{\rho}$......eq(1) We also know that; $Q=cm\Delta T$ This can be rearranged as: $m=\frac{Q}{c\Delta T}$ Thus equation(1) becomes: $V=\frac{Q}{c\rho \Delta T}$ We plug in the known values to obtain: $V=\frac{1\times 10^6(5)}{1\times 10^3\times 1(50-22)}=35.7m^3$
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