Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Exercises and Problems: 48

Answer

Please see the work below.

Work Step by Step

We know that the force of friction should be equal to the weight of the bat that is $F_{friction}=F_{gravity}$ $\implies \mu n=mg$ $\mu (ma)=mg$ This simplifies to: $a=\frac{g}{\mu}$ $a=\frac{9.8}{0.86}=11\frac{m}{s^2}$
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