Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Section 3.6 - Uniform Circular Motion - Example: 3.7

Answer

$ 1.52 \ h$

Work Step by Step

Using the equation for period, we find: $T = \sqrt{\frac{4\pi^2r}{a}}$ $T = \sqrt{\frac{4\pi^2(6.77\times10^6)}{8.73}}=5532\ s= 1.52 \ h$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.