Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Section 14.3 - Waves on a String - Example: 14.2

Answer

110 Newtons

Work Step by Step

We find: $F = \mu v^2 = (\frac{m}{L})(\frac{L}{t})^2 = \frac{mL}{t^2} = \frac{(5)(43)}{1.4^2} \approx 110 \ N$
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