## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 10 - Section 10.3 - Rotational Inertia and the Analog of Newton’s Law - Example - Page 177: 10.9

#### Answer

$a = \frac{ mg} {\frac{1}{2}M+m}$

#### Work Step by Step

We know the following equations: $ma = mg +( -T) = mg - \frac{1}{2}Ma$ $I = \frac{1}{2} MR^2$ $T = \frac{1}{2}Ma$ Solving the first equation for $a$ and combining these, we find: $a = \frac{ mg} {\frac{1}{2}M+m}$

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