Answer
$$F= 2.1 \times 10^{20} N $$
Work Step by Step
$$F= G \frac{m_{1} m_{2}}{d^{2}} = (6.67 \times 10^{-11} \frac {N \cdot m^{2}}{kg^{2}}) \frac{(7.4 \times 10^{22} kg )(6.0 \times 10^{24} kg)}{(3.8 \times 10^{8} m)^{2}} $$
Conceptual Physics (12th Edition)
by Hewitt, Paul G.
Published by
Addison-Wesley
ISBN 10:
0321909100
ISBN 13:
978-0-32190-910-7
Chapter 9 - Plug and Chug - Page 178: 35
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
