College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 32: 77

Answer

(a) 94.2 s (b) $7.00\times10^{4}\,gal$

Work Step by Step

(a) $Diameter\,2r=0.500\,m/s\times30.0\,s=15.0\,m$ We need to find the time taken to travel a distance equal to the circumference of a circle with diameter 15.0 m Circumference=$2\pi r=15.0\,m\times3.14=47.1\,m$ Time taken= $\frac{distance}{speed}=\frac{47.1\,m}{0.500\,m/s}=94.2\,s$ (b) $V=\pi r^{2}h$ In gallons, Volume $V=3.14\times(\frac{15.0\,m}{2})^{2}\times1.50\,m\times\frac{264.172\,gal}{1\,m^{3}}$ $=7.00\times10^{4}\,gal$
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