College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 8 - Problems - Page 320: 109


$L = 0.19~kg~m^2/s$

Work Step by Step

We can express the angular speed in units of rad/s: $3.0~rev/s \times \frac{2\pi~rad}{1~rev} = 18.85~rad/s$ We can find the angular momentum: $L = I~\omega$ $L = \frac{1}{2}MR^2~\omega$ $L = \frac{1}{2}(2.0~kg)(0.10~m)^2~(18.85~rad/s)$ $L = 0.19~kg~m^2/s$
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