College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 8 - Multiple-Choice Questions - Page 310: 5


The correct answer is: $(e) \frac{kg~m^2}{s}$

Work Step by Step

We can write an expression for angular momentum: $L = I \omega$ $I$ is the rotational inertia and it has units of $kg~m^2$ $\omega$ is angular velocity and it has units of $rad/s$ We can find the SI units for angular momentum: $(kg~m^2)(rad/s) = \frac{kg~m^2}{s}$ The correct answer is: $(e) \frac{kg~m^2}{s}$
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