College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 2 - Problems - Page 67: 62

Answer

$9.3\times10^{3}km$

Work Step by Step

"g" is given by $g=\frac{GM}{R^{2}}$ or, $R=\sqrt (\frac{GM}{g})=\sqrt \frac{6.674\times10^{-11}\times5.974\times10^{24}}{1.62}=1.57\times10^{4}km$ Thus the height above the surface = $1.57\times10^{4}-6.371\times10^{3}=9.3\times10^{3}km$
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